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By Pan W.

Prior to now 20 years, telecommunication and Web-enabled applied sciences have mixed to create a brand new box of information often called "Web-Based studying and instructing Technologies." the most target of Web-Based schooling: studying from adventure is to profit from college stories received whereas imposing and using those applied sciences. The e-book addresses many developments and concerns linked to Web-Based schooling, and explores the possibilities and difficulties confronting faculties and universities to successfully make the most of and deal with Web-Based schooling of their instructing environments.

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Swapping rows in a matrix is an elementary row operation. Let’s flip the Wildcat image by swapping rows. To begin, we’ll swap the image’s first and last rows. Then, the second and second to last rows are interchanged. We continue to flip the image by swapping rows i and n − i + 1 where n is the number of rows in the image. 2, we see how such operations would be performed on an image with five rows and four columns of pixels. This process of row swapping can be performed with matrix multiplication.

The image in (a) is the view of New York City looking north on Broadway between Grand and Broome streets in the 1850s. In (b), we see an aerial view of the city at that time. 24 When Life is Linear the vector u 2 = u1 − u2 . There is also the taxicab norm, which is comT puted as v 1 = x y 1 = |x| + |y|. Suppose we are interested in the points (−1, 5) and (2, 4). The disT T tance between them is the length of the vector u = −1 5 − 2 4 = T −3 1 , under the vector norm you choose. √ Using the Euclidean norm, the length of the vector is (−3)2 + (1)2 = 10, which again correlates to the Euclidean distance between the points.

The law of cosines helps derive a formula for the angle between vectors. Oscar rates American Hustle with a 0 and Gravity with a 5. Emmy rates the films 5 and 2, and I rate them −3 and 3. Each person’s ratings again becomes a vector. So, Oscar’s taste vector is 0 5 . Emmy’s vector is 5 2 , and mine is −3 3 . 1, we would find the value of u − v , where u and v are taste vectors. The two vectors that result in the smallest value are identified as most similar. This time, we’ll measure similarity as the angle between the taste vectors.

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